[New-bugs-announce] [issue9563] bad exception handling when giving no value to an option requiring one

Gwendal LE BIHAN report at bugs.python.org
Tue Aug 10 23:25:28 CEST 2010


New submission from Gwendal LE BIHAN <gwendal.lebihan.dev at gmail.com>:

Having created the parser this way:

optparser=OptionParser()
optparser.add_option("--share-dir",dest="share_dir",default="/usr/share")
options,args=optparser.parse_args()

And calling the program this way:

appname --share-dir

I get the following exception, which is not caught:

options,args=optparser.parse_args()
  File "/usr/lib/python2.6/optparse.py", line 1394, in parse_args
    stop = self._process_args(largs, rargs, values)
  File "/usr/lib/python2.6/optparse.py", line 1434, in _process_args
    self._process_long_opt(rargs, values)
  File "/usr/lib/python2.6/optparse.py", line 1509, in _process_long_opt
    option.process(opt, value, values, self)
UnboundLocalError: local variable 'value' referenced before assignment

----------
components: Library (Lib)
messages: 113560
nosy: Gwendal.LE.BIHAN
priority: normal
severity: normal
status: open
title: bad exception handling when giving no value to an option requiring one
type: behavior
versions: Python 2.6

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Python tracker <report at bugs.python.org>
<http://bugs.python.org/issue9563>
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