[New-bugs-announce] [issue8185] re.findall()

[Jean-Michel Fauth]

New submission from Jean-Michel Fauth <wxjmfauth at gmail.com>:

>>> sys.version
2.6.5 (r265:79096, Mar 19 2010, 21:48:26) [MSC v.1500 32 bit
(Intel)]
>>> import re
>>> re.match("[-+]?[0-9]+[.]?[0-9]*([eE][-+]?[0-9]+)?", "1.23e-4").group()
1.23e-4
>>> re.search("[-+]?[0-9]+[.]?[0-9]*([eE][-+]?[0-9]+)?", "1.23e-4").group()
1.23e-4
>>> for e in re.finditer("[-+]?[0-9]+[.]?[0-9]*([eE][-+]?[0-9]+)?", "1.23e-4"):
        print e.group()
        
1.23e-4

but

>>> re.findall("[-+]?[0-9]+[.]?[0-9]*([eE][-+]?[0-9]+)?", "1.23e-4")
['e-4']
>>> 

It seems re.findall() does not like patterns containing parentheses.

>>> re.findall("[-+]?[0-9]+[.]?[0-9]*[eE][-+]?[0-9]+", "1.23e-4")
['1.23e-4']
>>> 
>>> re.findall("a(b)?", "ab")
['b']
>>> re.findall("ab?", "ab")
['ab']
>>>

----------
components: Regular Expressions
messages: 101381
nosy: jmfauth
severity: normal
status: open
title: re.findall()
versions: Python 2.6

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Python tracker <report at bugs.python.org>
<http://bugs.python.org/issue8185>
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