[New-bugs-announce] [issue12107] TCP listening sockets created without FD_CLOEXEC flag

Christophe Devriese report at bugs.python.org
Thu May 19 12:09:57 CEST 2011


New submission from Christophe Devriese <christophe.devriese at gmail.com>:

The specific issue this is creating is that a malicious user could use this socket in a subprocess which is started from a library (ie. I'm using a .so, which calls fork/exec).

A second failure mode is starting a daemon from withing, say, a django application. Djano opens a TCP listening socket, then starts up a daemon to provide some sort of service in the background. The daemon keeps running and inherits the socket. Now you restart the django app.

It refuses to start ! Why ? Because the socket was inherited, the listening socket isn't actually closed, and this results in the socket being stuck in CLOSE_WAIT as long as the daemon is running.

It seems to me that it is almost never the case that you'd want a TCP listening socket to be preserved across exec, and not setting this flag should thus be considered a bug for 2 reasons :

1) it results in accidental disclosure of information that shouldn't be exposed in certain cases.
2) it can result in denial of service

Solution : 

update SocketServer.py :
  in the class TCPServer
  add the following 2 lines in __init__ after self.socket = socket( ...:
    flags = fcntl.fcntl(self.socket, fcntl.F_GETFD)
    fcntl.fcntl(self.socket, fcntl.F_SETFD, flags | fcntl.FD_CLOEXEC)

----------
messages: 136273
nosy: Christophe.Devriese
priority: normal
severity: normal
status: open
title: TCP listening sockets created without FD_CLOEXEC flag
type: security

_______________________________________
Python tracker <report at bugs.python.org>
<http://bugs.python.org/issue12107>
_______________________________________


More information about the New-bugs-announce mailing list