[New-bugs-announce] [issue12130] regex 0.1.20110514 findall overlapped not working with 'start of string' expression
Julian
report at bugs.python.org
Sat May 21 00:47:52 CEST 2011
New submission from Julian <jcerruti at gmail.com>:
Trying to use regex 0.1.2011051 with the overlapped=True feature
It works great, unless I have the 'start of string' (caret) character in my regular expression:
>>> regex.findall(r"a.*b","abadalaba",overlapped=True)
['abadalab', 'adalab', 'alab', 'ab']
>>> regex.findall(r"^a.*b","abadalaba",overlapped=True)
['abadalab']
----------
components: Regular Expressions
messages: 136405
nosy: jcerruti
priority: normal
severity: normal
status: open
title: regex 0.1.20110514 findall overlapped not working with 'start of string' expression
versions: Python 2.7
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<http://bugs.python.org/issue12130>
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