[New-bugs-announce] [issue21129] Segfault in python interpreter

[Mayank Gupta]

New submission from Mayank Gupta:

If I open the python interpreter:
$ python
Then type
def to_hex(i):
  result = hex(i)[2:]

My interpreter segfaults (EXC_BAD_ACCESS).
Here's a backtrace from lldb:
(lldb) bt
* thread #1: tid = 0x152e7f, 0x00000001002eff97 readline.so`call_readline + 647, queue = 'com.apple.main-thread', stop reason = EXC_BAD_ACCESS (code=1, address=0x0)
  * frame #0: 0x00000001002eff97 readline.so`call_readline + 647
    frame #1: 0x0000000100008852 Python`PyOS_Readline + 274
    frame #2: 0x000000010000a0a8 Python`tok_nextc + 104
    frame #3: 0x000000010000a853 Python`PyTokenizer_Get + 147
    frame #4: 0x000000010000544a Python`parsetok + 218
    frame #5: 0x00000001000e7722 Python`PyParser_ASTFromFile + 146
    frame #6: 0x00000001000e8983 Python`PyRun_InteractiveOneFlags + 243
    frame #7: 0x00000001000e8c6e Python`PyRun_InteractiveLoopFlags + 78
    frame #8: 0x00000001000e9451 Python`PyRun_AnyFileExFlags + 161
    frame #9: 0x00000001000ffc9f Python`Py_Main + 2111
    frame #10: 0x0000000100000f14 Python

I am using cpython 2.7.3.

----------
components: Interpreter Core
messages: 215351
nosy: mayank
priority: normal
severity: normal
status: open
title: Segfault in python interpreter
type: crash
versions: Python 2.7

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Python tracker <report at bugs.python.org>
<http://bugs.python.org/issue21129>
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