[New-bugs-announce] [issue33098] add implicit conversion for random.choice() on a dict

[Aristide Grange]

New submission from Aristide Grange <aristide.grange at gmail.com>:

In Python 3, the expression:

```python
random.choice(d)
```

where `d` is a `dict`, raises this error:

```
~/anaconda3/lib/python3.6/random.py in choice(self, seq)
    256         except ValueError:
    257             raise IndexError('Cannot choose from an empty sequence') from None
--> 258         return seq[i]
    259 
    260     def shuffle(self, x, random=None):

KeyError: 2
```

Converting `d` into a list restores the Python 2's behavior:

```python
random.choice(list(d))
```

I am aware that the keys of a dict have now their own type. But IMHO the error message is rather uninformative, and above all, couldn't this conversion be made implicitely under the hood?

----------
messages: 314062
nosy: Aristide Grange
priority: normal
severity: normal
status: open
title: add implicit conversion for random.choice() on a dict
type: enhancement
versions: Python 3.4

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Python tracker <report at bugs.python.org>
<https://bugs.python.org/issue33098>
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