[New-bugs-announce] [issue35146] Bad Regular Expression Broke re.findall()

[Dan Boxall]

New submission from Dan Boxall <dboxall at l3mtechnologies.com>:

Hi, I'm new to regular expressions and while playing around with them I tried this:

>>> rex = '*New Revision:.* ([0-9]+)'
>>> re.findall(rex, text)

and got this:

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "C:\Python\Python37\lib\re.py", line 223, in findall
    return _compile(pattern, flags).findall(string)
  File "C:\Python\Python37\lib\re.py", line 286, in _compile
    p = sre_compile.compile(pattern, flags)
  File "C:\Python\Python37\lib\sre_compile.py", line 764, in compile
    p = sre_parse.parse(p, flags)
  File "C:\Python\Python37\lib\sre_parse.py", line 930, in parse
    p = _parse_sub(source, pattern, flags & SRE_FLAG_VERBOSE, 0)
  File "C:\Python\Python37\lib\sre_parse.py", line 426, in _parse_sub
    not nested and not items))
  File "C:\Python\Python37\lib\sre_parse.py", line 651, in _parse
    source.tell() - here + len(this))
re.error: nothing to repeat at position 0

----------
components: Regular Expressions
messages: 329130
nosy: Callipygean, ezio.melotti, mrabarnett
priority: normal
severity: normal
status: open
title: Bad Regular Expression Broke re.findall()
versions: Python 3.7

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Python tracker <report at bugs.python.org>
<https://bugs.python.org/issue35146>
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