[New-bugs-announce] [issue41520] 3.8.5 regression, warnings.simplefilter('error', SyntaxWarning) does not raise.

[Matthias Bussonnier]

New submission from Matthias Bussonnier <bussonniermatthias at gmail.com>:

assuming 

    $ cat foo.py
    import warnings
    from codeop import compile_command

    warnings.simplefilter('error', SyntaxWarning)
    res = compile_command('1 is 1\n', symbol='exec')
    print('Res', res)

On 3.8.0...3.8.4 this correctly raises a SyntaxError:

 python  foo.py
Traceback (most recent call last):
  File "foo.py", line 5, in <module>
    res = compile_command('1 is 1\n', symbol='exec')
  File "/Users/bussonniermatthias/miniconda3/envs/38/lib/python3.8/codeop.py", line 122, in compile_command
    return _maybe_compile(_compile, source, filename, symbol)
  File "/Users/bussonniermatthias/miniconda3/envs/38/lib/python3.8/codeop.py", line 99, in _maybe_compile
    raise err1
  File "/Users/bussonniermatthias/miniconda3/envs/38/lib/python3.8/codeop.py", line 87, in _maybe_compile
    code1 = compiler(source + "\n", filename, symbol)
  File "/Users/bussonniermatthias/miniconda3/envs/38/lib/python3.8/codeop.py", line 102, in _compile
    return compile(source, filename, symbol, PyCF_DONT_IMPLY_DEDENT)
  File "<input>", line 1
SyntaxError: "is" with a literal. Did you mean "=="?



But will silently return None on 3.8.5

$ python  foo.py
Res None

----------
components: Interpreter Core
messages: 375152
nosy: mbussonn
priority: normal
severity: normal
status: open
title: 3.8.5 regression, warnings.simplefilter('error', SyntaxWarning) does not raise.
type: behavior
versions: Python 3.8

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Python tracker <report at bugs.python.org>
<https://bugs.python.org/issue41520>
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