[Numpy-discussion] erfc
Karthikesh Raju
karthik at james.hut.fi
Wed Jun 2 09:38:08 EDT 2004
Hi All,
Thankx to everyone for my previous "Random Numbers" question. Ok, do
we have the complementary error function in numarray?
i mean erfc(z) = 1 - erf(z)
= \frac{2}{\pi} \int_z^\infy e^{t^2}dt
(just used LaTeX notation, ran out of ideas to represent it otherwise)
Warm regards
Karthik
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Karthikesh Raju, email: karthik at james.hut.fi
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Helsinki University of Technology, Tel: +358-9-451 5389
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