[Numpy-discussion] fft output and input storage

[Warren Focke]

>>> print FFT.fft.__doc__
fft(a, n=None, axis=-1)

    Will return the n point discrete Fourier transform of a. n defaults to the
    length of a. If n is larger than a, then a will be zero-padded to make up
    the difference. If n is smaller than a, the first n items in a will be
    used.

    The packing of the result is "standard": If A = fft(a, n), then A[0]
    contains the zero-frequency term, A[1:n/2+1] contains the
    positive-frequency terms, and A[n/2+1:] contains the negative-frequency
    terms, in order of decreasingly negative frequency. So for an 8-point
    transform, the frequencies of the result are [ 0, 1, 2, 3, 4, -3, -2, -1].

    This is most efficient for n a power of two. This also stores a cache of
    working memory for different sizes of fft's, so you could theoretically
    run into memory problems if you call this too many times with too many
    different n's.
>>>

Hmph.  The style guide says I should've put a blank line on the end of
that docstring.  But I don't think there was a style guide then.

w

On Tue, 26 Jul 2005, Daniel Sheltraw wrote:

> Hello all
>
> Would someone please tell me how negative and positive
> frequencies are
> stored in the output of the Numerical Python fft?
>
> Cheers,
> Daniel
>
>
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