On Fri, 10 Feb 2006, Stefan van der Walt apparently wrote: > In Octave that would be > [1, 0, 1:4, 0, 1] > Using numpy we currently do > concatenate([[1, 0], arange(1,5), [0, 1]]) or > vstack(...) numpy.r_[1,0,range(1,5),0,1] fwiw, Alan Isaac