[Numpy-discussion] Re: array.argmax() question

Ryan Krauss ryanlists at gmail.com
Thu Feb 23 18:11:06 EST 2006

Is the right answer to just use flatten()?

i.e. ind=abs(mymat).argmax()

On 2/23/06, Ryan Krauss <ryanlists at gmail.com> wrote:
> Is this the expected behavior for array.argmax():
> ipdb> abs(real(disps)).max()
> Out[38]: 1.7373584411866401e-05
> ipdb> abs(real(disps)).argmax()
> Out[38]: 32
> ipdb> shape(disps)
> Out[38]: (11, 3)
> ipdb> disps[11,1]
> *** IndexError: invalid index
> ipdb> disps[10,1]
> Out[38]: 0j
> ipdb> disps[10,2]
> Out[38]: (-1.7373584411866401e-05+5.2046737124258386e-21j)
> Basically, I want to find the element with the largest absolute value
> in a matrix and use it to scale by.  But I need to correct for the
> possibility that the largest abs value may be from a negative number.
> So, I need to get the corresponding element itself.
> My array is shape (11,3) and argmax without an axis argument returns
> 32, which would be the index if the matrix was reshaped into a (33,)
> vector.  Is there a clean way to extract the element based on the
> output of argmax? (and in my case it is actually using the output of
> argmax to extract the element from the matrix without the abs).  Or do
> I need to reshape the matrix into a vector first?
> Thanks,
> Ryan

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