[Numpy-discussion] lexsort
Charles R Harris
charlesr.harris at gmail.com
Fri Jun 2 01:05:13 EDT 2006
Tom,
The list -- nee tuple, thanks Travis -- is the list of key sequences and
each key sequence can be a column in a matrix. So for instance if you wanted
to sort on a few columns of a matrix, say columns 2,1, and 0, in that order,
and then rearrange the rows so the columns were ordered, you would do
something like:
>>> a = randint(0,2,(7,4))
>>> a
array([[0, 0, 0, 1],
[0, 0, 1, 0],
[1, 0, 0, 1],
[0, 1, 0, 1],
[1, 1, 1, 0],
[0, 1, 1, 1],
[0, 1, 0, 1]])
>>> ind = lexsort((a[:,2],a[:,1],a[:,0]))
>>> sorted = a[ind]
>>> sorted
array([[0, 0, 0, 1],
[0, 0, 1, 0],
[0, 1, 0, 1],
[0, 1, 0, 1],
[0, 1, 1, 1],
[1, 0, 0, 1],
[1, 1, 1, 0]])
Note that the last key defines the major order.
Chuck
On 6/1/06, Tom Denniston <tom.denniston at alum.dartmouth.org> wrote:
>
> This function is really useful but it seems to only take tuples not
> ndarrays. This seems kinda strange. Does one have to convert the
> ndarray into a tuple to use it? This seems extremely inefficient. Is
> there an efficient way to argsort a 2d array based upon multiple
> columns if lexsort is not the correct way to do this? The only way I
> have found to do this is to construct a list of tuples and sort them
> using python's list sort. This is inefficient and convoluted so I was
> hoping lexsort would provide a simple solution.
>
> --Tom
>
>
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