Should numpy.sqrt(-1) return 1j rather than nan?

[David Cournapeau]

David Goldsmith wrote:
> Travis Oliphant wrote:
>   
>> What could be simpler? ;-)
>>     
> Having sqrt(-1) return 1j (without having to remember that in order to 
> get this, you have to write sqrt(-1+0j) instead).
>
>   
But this can sometimes lead to confusing errors hard to track when you 
don't want to treat complex numbers. That's one of the thing I hated in 
matlab, actually: if you don't want to handle complex numbers, you have 
to check regularly for it. So I don't think this is simpler.

David

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