[Numpy-discussion] numpy.nansum() behavior in 1.3.0

[Alan G Isaac]

On 6/1/2009 3:38 PM josef.pktd at gmail.com apparently wrote:
> Here's a good one:
> 
>>>> np.isnan([]).all()
> True
>>>> np.isnan([]).any()
> False


 >>> all([])
True
 >>> any([])
False

Cheers,
Alan Isaac