[Numpy-discussion] Use-case for np.choose

David Goldsmith d.l.goldsmith at gmail.com
Mon Nov 9 19:54:23 EST 2009


May I infer from the sudden silence that I finally have it?

DG

On Sun, Nov 8, 2009 at 8:50 PM, David Goldsmith <d.l.goldsmith at gmail.com>wrote:

> OK, let me see if I'm interpreting this example correctly:
>
> >>> c1=np.arange(2).reshape(2,1,1); c1
> array([[[0]],
>
>        [[1]]])
> >>> c2=2+np.arange(2).reshape(1,1,2); c2
> array([[[2, 3]]])
>
> >>> a=np.eye(2,dtype=int)
> >>> np.choose(a, [c1, c2])
> array([[[2, 0],
>         [0, 3]],
>
>        [[2, 1],
>         [1, 3]]])
>
> First, everything is being broadcast to (2,2,2); a is broadcast to [[[1,0],
> [0,1]], [[1,0], [0,1]]], c1 is broadcast to [[[0,0], [0,0]], [[1,1], [1,1]]]
> and c2 is broadcast to [[[2,3], [2,3]], [[2,3], [2,3]]].  Now result is
> created by "stepping through" broadcast a and using, respectively, the
> positionally corresponding element from broadcast c1 (resp. c2) if the value
> in a at the position is 0 (resp. 1).  At least, this gives the result above
> (but I have not examined other possible broadcasts of the arguments to see
> if they would also give the result - I conjectured what appeared to me to be
> the most "natural" broadcasts and checked to see if it worked and it does;
> is there something I should know - e.g., uniqueness of the result, or a rule
> governing how choose broadcasts - to *know* that the broadcasts above are
> indeed the broadcasts choose is using?)
>
> Thanks again,
>
> DG
>
> On Sun, Nov 8, 2009 at 8:19 PM, Anne Archibald <peridot.faceted at gmail.com>wrote:
>
>> 2009/11/8 David Goldsmith <d.l.goldsmith at gmail.com>:
>> > On Sun, Nov 8, 2009 at 7:40 PM, Anne Archibald <
>> peridot.faceted at gmail.com>
>> > wrote:
>> >>
>> >> As Josef said, this is not correct. I think the key point of confusion
>> is
>> >> this:
>> >>
>> >> Do not pass choose two arrays.
>> >>
>> >> Pass it one array and a *list* of arrays. The fact that choices can be
>> >> an array is a quirk we can't change, but you should think of the
>> >> second argument as a list of arrays,
>> >
>> > Fine, but as you say, one *can* pass choose an array as the second
>> argument
>> > and it doesn't raise an exception, so if someone is stupid/careless
>> enough
>> > to pass an array for `choices`, how is choose interpreting it as a
>> list?  Is
>> > the first dimension "list converted" (so that, e.g., my (2,1,2) example
>> is
>> > interpreted as a two element list, each of whose elements is a (1,2)
>> array)?
>>
>> It seems to me that this is the only reasonable interpretation, yes.
>> After all, arrays behave like sequences along the first axis, whose
>> elements are arrays of one less dimension. Thus if you pass an array,
>> any broadcasting happens ignoring the first axis, which is a rather
>> abnormal pattern for numpy broadcasting, but necessary here.
>>
>> As a bonus, I think this is what is implemented in current versions of
>> numpy. (In 1.2.1 it raises an exception if broadcasting is necessary.)
>>
>> Anne
>> _______________________________________________
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>> NumPy-Discussion at scipy.org
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>>
>
>
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