[Numpy-discussion] Problems creating numpy.array with a dtype
Jimmie Houchin
jlhouchin at gmail.com
Sat May 15 09:27:34 EDT 2010
On 5/15/2010 6:30 AM, josef.pktd at gmail.com wrote:
> On Sat, May 15, 2010 at 12:24 AM, Jimmie Houchin<jlhouchin at gmail.com> wrote:
>> def getArray(instrument, weekString=None):
>> ...
>> cur.execute(sql)
>> weekData = cur.fetchall()
>> wdata = []
>> lst = []
>> dtminute, dttypes = createDType()
>> for i in dttypes:
>> if i[1] == 'f8': lst.append(0.0)
>> elif i[1] == 'i1': lst.append(0)
>> else: lst.append('')
>> for m in weekData:
>> data = list(m)+lst[9:]
>> wdata.append(data)
>
> I think "data" here should be a tuple, i.e. tuple(data)
> structured arrays expect tuples for each element/row
>
> If this is not it, then you could provide a mini example of wdata with
> just a few rows.
>
>> return np.array(wdata,dtype=dtminute)
>>
>> The createDType() function works fine. The getArray() function fails with:
>> ValueError: Setting void-array with object members using buffer.
>
> cryptic exceptions messages in array construction usually means there
> is some structure in the argument data that numpy doesn't understand,
> I usually work with trial and error for a specific example
>
> Josef
Hello Josef,
Wrapping data, tuple(list(m)+lst[9:])
works.
Thanks.
For some reason I was under the impression that numpy accepted either
lists or tuples as long as the shape of the structure, and the data
types was the same as the dtype array structure that it is filling.
Is there a particular reason this is not so?
Again, thanks. I can now get rid of my moderately less elegant, but
working second version.
Jimmie
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