[Numpy-discussion] LapackError:non-native byte order

[braingateway]

Matthew Brett :
> Hi,
>
> On Mon, Nov 8, 2010 at 10:34 AM, Pauli Virtanen <pav at iki.fi> wrote:
>   
>> Mon, 08 Nov 2010 19:31:31 +0100, Pauli Virtanen wrote:
>>
>>     
>>> ma, 2010-11-08 kello 18:56 +0100, LittleBigBrain kirjoitti:
>>>       
>>>> In my system '<' is the native byte-order, but unless I change the
>>>> byte-order label to '=', it won't work in linalg sub-module, but in
>>>> others works OK. I am not sure whether this is an expected behavior or
>>>> a bug?
>>>>         
>>>>>>> import sys
>>>>>>> sys.byteorder
>>>>>>>               
>>>> 'little'
>>>>         
>>>>>>> a.dtype.byteorder
>>>>>>>               
>>>> '<'
>>>>         
>>>>>>> b.dtype.byteorder
>>>>>>>               
>>>> '<'
>>>>         
>>> The error is here: it's not possible to create such dtypes via any Numpy
>>> methods -- the '<' (or '>') is always normalized to '='. Numpy and
>>> several other modules consequently assume this normalization.
>>>
>>> Where do `a` and `b` come from?
>>>       
>> Ok, `x.newbyteorder('<')` seems to do this. Now I'm unsure how things are
>> supposed to work.
>>     
>
> Yes - it is puzzling that ``x.newbyteorder('<')`` makes arrays that
> are confusing to numpy.  If numpy generally always normalizes to the
> system endian to '=' then should that not also be true of
> ``newbyteorder``?
>
> See you,
>
> Matthew
>   
I agree, at it is not documented or hard to find. I think usually all 
users will assume '<' is the same as '=' on normal 'little' system.

Thanks for reply,

LittleBigBrain
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