[Numpy-discussion] indexing question
John Salvatier
jsalvati at u.washington.edu
Mon Nov 22 14:20:35 EST 2010
I didn't realize the x's and y's were varying the first time around.
There's probably a way to omit it, but I think the conceptually
simplest way is probably what you had to begin with. Build an index by
saying i = numpy.arange(0, t.shape[0])
then you can do t[i, x,y]
On Mon, Nov 22, 2010 at 11:08 AM, Christopher Barker
<Chris.Barker at noaa.gov> wrote:
> On 11/21/10 11:37 AM, Ernest Adrogué wrote:
>>> so you want
>>>
>>> t[:,x,y]
>>
>> I tried that, but it's not the same:
>>
>> In [307]: t[[0,1],x,y]
>> Out[307]: array([1, 7])
>>
>> In [308]: t[:,x,y]
>> Out[308]:
>> array([[1, 3],
>> [5, 7]])
>
> what is your t? Here's my example, which I think matches what you asked for:
>
> In [1]: import numpy as np
>
> In [2]: a = np.arange(12)
>
> In [3]: a.shape = (3,2,2)
>
> In [4]: a
> Out[4]:
> array([[[ 0, 1],
> [ 2, 3]],
>
> [[ 4, 5],
> [ 6, 7]],
>
> [[ 8, 9],
> [10, 11]]])
>
> In [5]: a[:,1,0]
> Out[5]: array([ 2, 6, 10])
>
>
>
>
> --
> Christopher Barker, Ph.D.
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>
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