[Numpy-discussion] Array as Variable using "from cdms2 import MV2 as MV"
josef.pktd at gmail.com
josef.pktd at gmail.com
Mon Apr 25 03:17:42 EDT 2011
On Mon, Apr 25, 2011 at 2:50 AM, dileep kunjaai <dileepkunjaai at gmail.com> wrote:
> Dear sir,
>
> I am have 2 mxn numpy array say "obs" & "fcst". I have to
> calculate sum of squre of (obs[i, j]-fcst[i, j]) using from cdms2
> import MV2 as MV in CDAT without using "for" loop.
>
> For example:
> obs=
> [0.6 1.1 0.02 0.2 0.2
> 0.8 0. 0. 0.4 0.8
> 0.5 5.5 1.5 0.5 1.5
> 3.5 0.5 1.5 5.0 2.6
> 5.1 4.1 3.2 2.3 1.5
> 4.4 0.9 1.5 2. 2.3
> 1.1 1.1 1.5 12.6 1.3
> 2.2 12 1.7 1.6 15
> 1.9 1.5 0.9 2.5 5.5 ]
>
>
>
> fcst=
>
> [0.7 0.1 0.2 0.2 0.2
> 0.3 0.8 0. 0. 0.
> 0.5 0.5 0.5 0.5 0.5
> 0.7 1. 1.5 2. 2.6
> 5.1 4.1 3.2 2.3 1.5
> 0.7 1. 1.5 2. 2.3
> 1.1 1.1 1.1 12.7 1.3
> 2.2 2. 1.7 1.6 1.5
> 1.9 1.5 0.9 0.5 7.5]
>
> here "obs" and "fcst" are numpy array
> I give
>
> obs=MV.array(obs)
> fcst=MV.array(fcst)
>
> Then it become
>
>
> sbst=obs-fcst
>
>>> subst=
> [[ -0.1 1. -0.18 0. 0. ]
> [ 0.5 -0.8 0. 0.4 0.8 ]
> [ 0. 5. 1. 0. 1. ]
> [ 2.8 -0.5 0. 3. 0. ]
> [ 0. 0. 0. 0. 0. ]
> [ 3.7 -0.1 0. 0. 0. ]
> [ 0. 0. 0.4 -0.1 0. ]
> [ 0. 10. 0. 0. 13.5 ]
> [ 0. 0. 0. 2. -2. ]]
>
> But i dont know how to find sum of squre of each term....(Actually my aim is
> to finding MEAN SQUARED ERROR)
(sbst**2).sum()
or with sum along columns
(sbst**2).sum(0)
explanation is in the documentation
Josef
>
>
>
>
> Thanking you...................
>
> --
> DILEEPKUMAR. R
> J R F, IIT DELHI
>
>
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