# [Numpy-discussion] Array of size 'n' with common difference < 1

dileep kunjaai dileepkunjaai at gmail.com
Fri Apr 29 11:55:47 EDT 2011

```Thank you sir: thank you....very much for ur time and
consideration..................

On Fri, Apr 29, 2011 at 9:11 PM, Christopher Barker
<Chris.Barker at noaa.gov>wrote:

> On 4/29/11 12:31 AM, pratik wrote:
> > On Friday 29 April 2011 12:56 PM, dileep kunjaai wrote:
> >> Dear sir,
> >> I am trying to make an array of varies from -60 to 90 with difference
> >> 0.25. I tried the following command ...
>
> >> >>import numpy as N
> >> lat=N.array(xrange(-6000, 9000, 25), dtype=float)
> >> print lat/100
>
> xrange() (or range(), or np.arange()) is almost never the right solution
> for floating point ranges, due to the intricacies of floating point
> precision.
>
> > lat =numpy.mgrid[-60:90:.25]
>
> or np.linspace:
>
> np.linspace(-60,90,((60.+90.)*4. + 1))
>
> ((60.+90.)*4. + 1) is the number of points you want -- the +1 because
> you want both end points.
>
> mgrid is usually used for 2-d (or higher) grids, though it looks like it
> makes sense for this use, too, though note that it doesn't give you both
> endpoints in this case. From the docs:
>
> """If the step length is not a
>     complex number, then the stop is not inclusive.
> """
>
> and an example:
>
> In [15]: np.mgrid[-1:3:.25]
> Out[15]:
> array([-1.  , -0.75, -0.5 , -0.25,  0.  ,  0.25,  0.5 ,  0.75,  1.  ,
>         1.25,  1.5 ,  1.75,  2.  ,  2.25,  2.5 ,  2.75])
>
> I think this is too bad, actually, because we're back to range()-type
> tricks to get the end point:
>
> In [20]: np.mgrid[-1:3.25:.25]
> Out[20]:
> array([-1.  , -0.75, -0.5 , -0.25,  0.  ,  0.25,  0.5 ,  0.75,  1.  ,
>         1.25,  1.5 ,  1.75,  2.  ,  2.25,  2.5 ,  2.75,  3.  ])
>
>
> -Chris
>
>
>
> --
> Christopher Barker, Ph.D.
> Oceanographer
>
> Emergency Response Division
> NOAA/NOS/OR&R            (206) 526-6959   voice
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>
> Chris.Barker at noaa.gov
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>

--
DILEEPKUMAR. R
J R F, IIT DELHI
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