[Numpy-discussion] indexing of rank-0 structured arrays: why not?

[Nils Becker]

Robert,

your answer does work: after indexing with () I can then further index
into the datatype.

In [115]: a_rank_0[()][0]
Out[115]: 0.0

I guess I just found the fact confusing that a_rank_1[0] and a_rank_0
compare and print equal but behave differently under indexing.

More precisely if I do
In [117]: b = a_rank_1[0]

then

In [118]: b.shape
Out[118]: ()

and

In [120]: a_rank_0 == b
Out[120]: True

but

In [119]: b[0]
Out[119]: 0.0

works but a_rank_0[0] doesn't. I thought b is a rank-0 array which it
apparently is not since it can be indexed. So maybe b[0] should fail for
consistency?

N.