[Numpy-discussion] numpy.int32 is not subclass of int, but numpy.int64 is

[MACKEITH Andrew]

Could someone explain this?

An instance of numpy.int32 is not an instance of int or numpy.int.
An instance of numpy.int64 is an instance of int and numpy.int.

I don't know if it is a bug in my linux build.

Andrew

>python26
Python 2.6.2 (r262:71600, Jul  8 2010, 11:49:56)
[GCC 4.1.2 20070115 (SUSE Linux)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>>
>>> import numpy
>>> a = numpy.array((1,2,3))
>>> type(a[0])
<type 'numpy.int64'>
>>> isinstance(a[0], int)
True
>>> isinstance(a[0], numpy.int)
True
>>> seven = numpy.int64(7)
>>> isinstance(seven, numpy.int)
True
>>> isinstance(seven, int)
True
>>>
>>> five = numpy.int32(5)
>>> isinstance(five, numpy.int)
False
>>> isinstance(five, int)
False
>>> five
5
>>> seven
7
>>> issubclass(numpy.int64, numpy.int)
True
>>> issubclass(numpy.int32, numpy.int)
False
>>>
>>> import sys
>>> sys.maxint
9223372036854775807
>>> import platform
>>> print  platform.platform()
Linux-2.6.32.12-0.7-default-x86_64-with-SuSE-11-x86_64
>>>




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