[Numpy-discussion] Finding the same value in List
Todd
toddrjen at gmail.com
Wed Apr 17 05:02:24 EDT 2013
On Wed, Apr 17, 2013 at 10:46 AM, Todd <toddrjen at gmail.com> wrote:
> x,i=numpy.unique(y, return_inverse=True)
> f=[numpy.where(i==ind) for ind in range(len(x))]
>
>
>
A better version would be (np.where returns tuples, but we don't want
tuples):
x,i=numpy.unique(y, return_inverse=True)
f=[numpy.where(i==ind)[0] for ind in range(len(x))]
You can also do it this way, but it is much harder to read IMO:
x=numpy.unique(y)
f=numpy.split(numpy.argsort(y),
numpy.nonzero(numpy.diff(numpy.sort(y)))[0]+1)
This version figures out the indexes needed to put the values of y in
sorted order (the same order x uses), then splits it into sub-arrays based
on value. The principle is simpler but the implementation looks like clear
to me.
Note that these are only guaranteed to work on 1D arrays, I have not tested
them on multidimensional arrays
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