[Numpy-discussion] Array accumulation in numpy
Tony Ladd
tladd at che.ufl.edu
Tue Feb 19 10:24:25 EST 2013
Thanks to all for a very quick response. np.bincount does what I need.
Tony
On 02/19/2013 10:04 AM, Benjamin Root wrote:
>
>
> On Tue, Feb 19, 2013 at 10:00 AM, Tony Ladd <tladd at che.ufl.edu
> <mailto:tladd at che.ufl.edu>> wrote:
>
> I want to accumulate elements of a vector (x) to an array (f) based on
> an index list (ind).
>
> For example:
>
> x=[1,2,3,4,5,6]
> ind=[1,3,9,3,4,1]
> f=np.zeros(10)
>
> What I want would be produced by the loop
>
> for i=range(6):
> f[ind[i]]=f[ind[i]]+x[i]
>
> The answer is f=array([ 0., 7., 0., 6., 5., 0., 0., 0.,
> 0., 3.])
>
> When I try to use implicit arguments
>
> f[ind]=f[ind]+x
>
> I get f=array([ 0., 6., 0., 4., 5., 0., 0., 0., 0., 3.])
>
>
> So it takes the last value of x that is pointed to by ind and adds
> it to
> f, but its the wrong answer when there are repeats of the same
> entry in
> ind (e.g. 3 or 1)
>
> I realize my code is incorrect, but is there a way to make numpy
> accumulate without using loops? I would have thought so but I cannot
> find anything in the documentation.
>
> Would much appreciate any help - probably a really simple question.
>
> Thanks
>
> Tony
>
>
> I believe you are looking for the equivalent of accumarray in Matlab?
>
> Try this:
>
> http://www.scipy.org/Cookbook/AccumarrayLike
>
> It is a bit touchy about lists and 1-D numpy arrays, but it does the job.
> Also, I think somebody posted an optimized version for simple sums
> recently to this list.
>
> Cheers!
> Ben Root
>
>
>
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--
Tony Ladd
Chemical Engineering Department
University of Florida
Gainesville, Florida 32611-6005
USA
Email: tladd-"(AT)"-che.ufl.edu
Web http://ladd.che.ufl.edu
Tel: (352)-392-6509
FAX: (352)-392-9514
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