[Numpy-discussion] could anyone check on a 32bit system?
Matthew Brett
matthew.brett at gmail.com
Wed May 1 13:24:37 EDT 2013
HI,
On Wed, May 1, 2013 at 9:09 AM, Yaroslav Halchenko <lists at onerussian.com> wrote:
>
> On Wed, 01 May 2013, Nathaniel Smith wrote:
>> > not sure there is anything to fix here. Third-party code relying on a
>> > certain outcome of rounding error is likely incorrect anyway.
>
>> Yeah, seems to just be the standard floating point indeterminism.
>> Using Matthew's numbers and pure Python floats:
>
>> In [9]: (0.49505185 + 0.53529587) + -0.13461665
>> Out[9]: 0.89573107
>
>> In [10]: 0.49505185 + (0.53529587 + -0.13461665)
>> Out[10]: 0.8957310700000001
>
>> In [11]: _9 - _10
>> Out[11]: -1.1102230246251565e-16
>
>> Looks like a bug in pymvpa or its test suite to me.
>
> well -- sure thing we will "fix" the unittest to not rely on precise
> correspondence any longer since released 1.7.1 is effected. So it is not
> a matter of me avoiding "fixing" pymvpa's "bug".
>
> I brought it to your attention because
>
> 1. from e.g.
>
> np.sum(data[:, 0]) - np.sum(data, axis=0)[0]
>
> which presumably should be the same order of additions for 0-th column it is
> not clear that they do not have to be identical.
I agree it's surprising, but I guess it's reasonable for numpy to
reserve the right to add these guys up in whatever order it chooses,
and (in this case) maybe a different order for the axis=None, axis=X
cases.
Also, y'all may have noticed that it is the presence of the second
vector in the array which causes the difference in the sums of the
first (see my first email in this thread). If this is an order
effect I guess this means that the order of operations in an sum(a,
axis=X) operation depends on the shape of the array. And it looks
like it depends on memory layout:
In [24]: data = np.array([[ 0.49505185, 0],
....: [ 0.53529587, 0],
....: [-0.13461665, 0]])
In [25]: np.sum(data[:, 0]) - np.sum(data, axis=0)[0]
Out[25]: 1.1102230246251565e-16
In [26]: data_F = np.array(data, order='F')
In [27]: np.sum(data_F[:, 0]) - np.sum(data_F, axis=0)[0]
Out[27]: 0.0
Do we allow the results to be different for different memory layout?
> 2. so far they were identical across many numpy releases
>
> 3. they are identical on other architectures (e.g. amd64)
To me that is surprising. I would have guessed that the order is the
same on 32 and 64 bit, but something about the precision of
intermediate operations is different. I don't know enough about
amd64 to guess what that could be. Bradley's suggestion seems kind of
reasonable but it's strange that numpy should use intel-80 bit
intermediate values differently for 32 and 64 bit.
Cheers,
Matthew
More information about the NumPy-Discussion
mailing list