[Numpy-discussion] Custom floating point representation to IEEE 754 double
oscar.j.benjamin at gmail.com
Wed Feb 26 06:37:06 EST 2014
On 26 February 2014 00:35, Daniele Nicolodi <daniele at grinta.net> wrote:
> "simpler" in my original email has to be read as involving less
> operations and thus more efficient, not simpler to understand, indeed it
> is already a simple implementation of the definition. What I would like
> to know is if there are some smart shortcuts to make the computation
> more efficient.
Sorry I misunderstood your question. How about this:
data = frombytes(data)
return float(data & 0x0fffffffffffff) * 2 ** ((data >> 52) - 35)
That's roughly how you'd do it in C except for the 2**exponent part.
I'm not sure what Cython would do with that. If exponent is positive
then you can replace that with 1<<exponent or if negative divide by
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