[Numpy-discussion] (no subject)
Jonathan Helmus
jjhelmus at gmail.com
Thu Sep 18 13:14:51 EDT 2014
On 09/18/2014 12:01 PM, Chris Barker wrote:
> Well,
>
> First of all, numpy and the python math module have a number of
> differences when it comes to handling these kind of special cases --
> and I think that:
>
> 1) numpy needs to do what makes the most sense for numpy and NOT
> mirror the math lib.
>
> 2) the use-cases of the math lib and numpy are different, so they
> maybe _should_ have different handling of this kind of thing.
>
> 3) I'm not sure that the core devs think these kinds of issues are
> "wrong" 'enough to break backward compatibility in subtle ways.
>
> But it's a fun topic in any case, and maybe numpy's behavior could be
> improved.
>
> My vote is that NumPy is correct here. I see no reason why
> >>> float('inf') / 1
> and
> >>> float('inf') // 1
>
> should return different results.
>
>
> Well, one argument is that "floor division" is supposed to return an
> integer value, and that inf is NOT an integer value. The integral part
> of infinity doesn't exist and thus is Not a Number.
>
But nan is not an integer value either:
>>> float('inf') // 1
nan
>>> int(float('inf') // 1)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: cannot convert float NaN to integer
Perhaps float('inf') // 1 should raise a ValueError directly since there
is no proper way perform the floor division on infinity.
- Jonathan Helmus
> You also get some weird edge cases around the mod operator.
>
> -Chris
>
> --
>
> Christopher Barker, Ph.D.
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