[Numpy-discussion] How to find indices of values in an array (indirect in1d) ?

[Mark Miller]

I'm not 100% sure that I get the question, but does this help at all?

>>> a = numpy.array([3,2,8,7])
>>> b = numpy.array([1,3,2,4,5,7,6,8,9])
>>> c = set(a) & set(b)
>>> c #contains elements of a that are in b (and vice versa)
set([8, 2, 3, 7])
>>> indices = numpy.where([x in c for x in b])[0]
>>> indices #indices of b where the elements of a in b occur
array([1, 2, 5, 7], dtype=int64)

-Mark


On Wed, Dec 30, 2015 at 6:45 AM, Nicolas P. Rougier <
Nicolas.Rougier at inria.fr> wrote:

>
> I’m scratching my head around a small problem but I can’t find a
> vectorized solution.
> I have 2 arrays A and B and I would like to get the indices (relative to
> B) of elements of A that are in B:
>
> >>> A = np.array([2,0,1,4])
> >>> B = np.array([1,2,0])
> >>> print (some_function(A,B))
> [1,2,0]
>
> # A[0] == 2 is in B and 2 == B[1] -> 1
> # A[1] == 0 is in B and 0 == B[2] -> 2
> # A[2] == 1 is in B and 1 == B[0] -> 0
>
> Any idea ? I tried numpy.in1d with no luck.
>
>
> Nicolas
>
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