[Numpy-discussion] 'nansqrt' function?

[Mauro Cavalcanti]

Chuck,

Sure, using numpy.sqrt works fine.

Thank you very much.

Best regards,

Em qua, 13 de fev de 2019 às 19:09, Charles R Harris <
charlesr.harris at gmail.com> escreveu:

>
>
> On Wed, Feb 13, 2019 at 1:35 PM Mauro Cavalcanti <maurobio at gmail.com>
> wrote:
>
>> Dear ALL,
>>
>> In the process of porting an existing (but abandoned) package to the
>> latest version of Numpy, I stumbled upon a call to a 'numpy.nansqrt'
>> function, which seems not to exist.
>>
>> Here is the specific code:
>>
>> def normTrans(y):
>>     denom = np.nansqrt(np.nansum(y**2))
>>     return y/denom
>>
>> As far as I could find, there is no such 'nansqrt' function in the
>> current version of Numpy, so I suspect that the above code has not been
>> properly tested.
>>
>> Am I right, or that function had existed in some past version of Numpy?
>>
>> Thanks in advance for any comments or suggestions.
>>
>>
> I don't recall any such function, but  nansum will not result in any nans,
> so plain old sqrt should work.
>
> Chuck
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-- 
Dr. Mauro J. Cavalcanti
E-mail: maurobio at gmail.com
Web: http://sites.google.com/site/maurobio
"Life is complex. It consists of real and imaginary parts."
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