[pypy-dev] Call rpython from outside

[Maciej Fijalkowski]

lltype.Struct is a GC-managed struct, you don't want to have this as a
part of API (use CStruct)

On Mon, Jul 10, 2017 at 6:15 PM, Aleksandr Koshkin
<tinysnippets at gmail.com> wrote:
> Here is a link to a function that buggs me.
> https://github.com/magniff/rere/blob/master/rere/vm/vm_main.py#L110
> I am using this headers for CFFI:
> https://github.com/magniff/rere/blob/master/rere/build/vm_headers.h
>
> 2017-07-10 17:03 GMT+03:00 Aleksandr Koshkin <tinysnippets at gmail.com>:
>>
>> Sup, guys.
>> I want my rpython function to be invokable from outside world specifically
>> be python. I have wrapped my function with entrypoint_highlevel and it
>> appeared in shared object. So far so good. As a first argument this function
>> takes a pointer to a C struct, and there is a problem. I have precisely
>> recreated this struct in RPython as a lltypes.Struct (not rffi.CStruct) and
>> annotated by this object my entrypoint signature, but it seams that some
>> fields of the passed struct are messed up (shifted basically). Could it be
>> because I used Struct instead of CStruct? I am using CFFI as a binding
>> generator.
>>
>> --
>> Kind regards, Aleksandr Koshkin.
>
>
>
>
> --
> Kind regards, Aleksandr Koshkin.
>
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