[Python-3000] PEP 3124 - Overloading, Generic Functions, Interfaces, etc.
talin at acm.org
Tue May 1 18:13:29 CEST 2007
Phillip J. Eby wrote:
> Proceeding to the "Next" Method
> If the first parameter of an overloaded function is named
> ``__proceed__``, it will be passed a callable representing the next
> most-specific method. For example, this code::
> def foo(bar:object, baz:object):
> print "got objects!"
> def foo(__proceed__, bar:int, baz:int):
> print "got integers!"
> return __proceed__(bar, baz)
I don't care for the idea of testing against a specially named argument.
Why couldn't you just have a different decorator, such as
"overload_chained" which triggers this behavior?
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