[Python-3000] [Python-Dev] PEP 367: New Super

Guido van Rossum guido at python.org
Tue May 29 04:37:47 CEST 2007


Hi Tim,

I've gone ahead and cooked up a tiny demo patch that uses im_class to
store what you called im_type. Because I don't have the parser changes
ready yet, this requires you to declare a keyword-only arg named
'super'; this triggers special code that set it to super(im_class,
im_self).

http://python.org/sf/1727209

I haven't tried to discover yet how much breaks due to the change of
semantics for im_class.

--Guido

On 5/27/07, Guido van Rossum <guido at python.org> wrote:
> On 5/27/07, Tim Delaney <timothy.c.delaney at gmail.com> wrote:
> > Guido van Rossum wrote:
> >
> > > The bound method object isn't stored in the class -- it's created by
> > > the "C.method" or "inst.method" getattr operation. I don't see how
> > > this would introduce a cycle.
> > >
> > >> If we store the class, we can store it as a weakref - the when the
> > >> super object is created, a strong reference to the class exists.
> >
> > We need to create some relationship between the unbound method and the
> > class. So the class has a reference to the unbound method, and the unbound
> > method has a reference to the class, thus creating a cycle. Bound methods
> > don't come into it - it's the unbound method that's the problem.
>
> Still wrong, I think. The unbound method object *also* isn't stored in
> the class. It's returned by the C.method operation. Compare C.method
> (which returns an unbound method) to C.__dict__['method'] (which
> returns the actual function object stored in the class).
>
> > > Since class and type are synonym (as you say) having both im_class and
> > > im_type would be a bad idea.
> >
> > I'm struggling to think of another, not too complicated name that conveys
> > the same information.
>
> Keep trying. im_type is not acceptable. :-)
>
> --
> --Guido van Rossum (home page: http://www.python.org/~guido/)
>


-- 
--Guido van Rossum (home page: http://www.python.org/~guido/)


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