[Python-bugs-list] [ python-Bugs-508665 ] Improvement of cgi.parse_qsl function
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noreply@sourceforge.net
Fri, 25 Jan 2002 12:24:01 -0800
Bugs item #508665, was opened at 2002-01-25 12:23
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http://sourceforge.net/tracker/?func=detail&atid=105470&aid=508665&group_id=5470
Category: Python Library
Group: Python 2.2
Status: Open
Resolution: None
Priority: 5
Submitted By: Christoph Zwerschke (cito)
Assigned to: Nobody/Anonymous (nobody)
Summary: Improvement of cgi.parse_qsl function
Initial Comment:
I found the parsing function "parse_qsl" in the
module "cgi" to have some flaws. Especially, empty
names are allowed, even if empty values are explicitly
disallowed. If the latter are allowed, "?name=" is
accepted, while "?name" is ignored. Often you want to
use links like "?logout" or "?help". This is not
possible, even if empty values are explicitly allowed.
Also, "strict parsing" objects to "?name=", while it
ignores "?name=a=b=c". My improvement suggestion:
------------- use ----------
for name_value in pairs:
if strict_parsing:
nv = name_value.split('=', 2)
if len(nv) != 2 or not len(nv[0]):
raise ValueError, "bad query field: %s" %
`name_value`
else:
nv = name_value.split('=', 1).append('')
if not len(nv[0]):
continue
if len(nv[1]) or keep_blank_values:
name = urllib.unquote(nv[0].replace('+', ' '))
value = urllib.unquote(nv[1].replace('+', ' '))
r.append((name, value))
----------- instead of --------
for name_value in pairs:
nv = name_value.split('=', 1)
if len(nv) != 2:
if strict_parsing:
raise ValueError, "bad query field: %s" %
`name_value`
continue
if len(nv[1]) or keep_blank_values:
name = urllib.unquote(nv[0].replace('+', ' '))
value = urllib.unquote(nv[1].replace('+', ' '))
r.append((name, value))
----------------------------------------------------------------------
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http://sourceforge.net/tracker/?func=detail&atid=105470&aid=508665&group_id=5470