[Python-bugs-list] [ python-Bugs-528274 ] Nested Scopes bug (Confirmed)
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Wed, 13 Mar 2002 01:38:05 -0800
Bugs item #528274, was opened at 2002-03-11 00:38
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Category: None
Group: Python 2.2
>Status: Open
Resolution: Wont Fix
Priority: 5
Submitted By: Alex A. Naanou (alex_nanou)
Assigned to: Jeremy Hylton (jhylton)
Summary: Nested Scopes bug (Confirmed)
Initial Comment:
Bug confirmed.
description:
names that a in a scope just above the scome of the
nested block (function) do not appear that functions
globals thus bracking SOME (!) of the code that uses
them. in particular the eval function, and all code
that explicitly searces the name in the globals.
code:
//see the attached file.
output:
- a NameError raised in function nested_1:
'NameError: global name 'a' is not defined'
- a NameError raised in function nested_2:
'NameError: name 'a' is not defined'
workarround:
explicitly pass the variable to the function as its
default argument (as in nested_0).
NOTE: declaring the name global does not work (as
shown in function nested_1).
//see the attached file for more details.
test results:
there appears to be a gap between the globals and the
locals of a nested function.
test systems:
WIN2K v.5.00.2195 SP2
- ActivePython 2.2 Alpha 2 build 1 (ActiveState)
Python 2.2a2+ (#22, Sep 5 2001, 14:10:41) [MSC 32 bit
(Intel)] on win32
- Python 2.2 (#1, Dec 31 2001, 15:21:18) [GCC 2.95.3-5
(cygwin special)] on cygwin
FreeBSD 4.5 (LocalBuild)
Python2.2 //I do not remember the exact build.
With Respect..
Alex.
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>Comment By: Martin v. Löwis (loewis)
Date: 2002-03-13 10:38
Message:
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The attached script also has the example
def f(x):
a = x
def g():
print a
return eval('a')
return g
f(3)()
which currently produces
3
Traceback (most recent call last):
File "a.py", line 8, in ?
f(3)()
File "a.py", line 5, in g
return eval('a')
File "<string>", line 0, in ?
NameError: name 'a' is not defined
I believe this is a bug, since the variable a is referenced
by the program text of the block that contains the call to
eval(); thus, accessing a inside eval should work well;
Reopening.
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Comment By: Jeremy Hylton (jhylton)
Date: 2002-03-12 23:34
Message:
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I just checked the language reference, Section A.3.2:
> The builtin functions eval() and input() can not access
free
> variables unless the variables are also referenced by the
> program text of he block that contains the call to eval()
> or input().
----------------------------------------------------------------------
Comment By: Jeremy Hylton (jhylton)
Date: 2002-03-12 23:31
Message:
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I think the bug report is trying to say that the error in
the following code snippet is unexpected:
def f(x):
a = x
def g():
return eval('a')
return g
f(3)()
I'm not sure what the nested scopes appendix in the ref
manual says, but I don't see that this is a bug I care to
fix. (If it's a bug at all.) I don't believe the behavior
of eval() is defined with respect to free variables bound in
enclosing scopes. In practical terms, the compiler has no
way to know that g() will try to access a in f().
----------------------------------------------------------------------
Comment By: Martin v. Löwis (loewis)
Date: 2002-03-11 08:16
Message:
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It is not clear from your report what bug you are reporting.
Please structure a bug report in the following way:
- what did you do (you've explained this, providing a script)
- what happened (you've also reported that)
- what did you expect to happen instead (this is hard to
find in your report)
- why do you believe that the bug is in Python and not in
your understanding of the language (optional)
Analizing what you got as output: in your report:
- NameError in nested_1: This is not a bug. You declare a as
a global variable, yet there is no global variable with that
name, hence the NameError.
- NameError in nested_2: This appears to be a bug. See
http://www.python.org/doc/current/ref/dynamic-features.html
for a discussion of nested scopes and dynamic features. In
your example, you reference the variable 'a' before using it
in eval(), so it should be available to eval(). Notice,
however, that removing the variable access from nested_2
also makes it unavailable to eval().
In the script, you argue that the variable should be either
global or local. This is not true in Python 2.2, see
http://www.python.org/doc/current/ref/nested-scopes.html
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