[Python-bugs-list] [ python-Bugs-666700 ] os.popen+() can take string list and bypass shell.

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Bugs item #666700, was opened at 2003-01-12 16:45
You can respond by visiting: 
https://sourceforge.net/tracker/?func=detail&atid=105470&aid=666700&group_id=5470

Category: Documentation
Group: Python 2.2.2
Status: Open
Resolution: None
Priority: 5
Submitted By: Dani (asqui)
Assigned to: Nobody/Anonymous (nobody)
Summary: os.popen+() can take string list and bypass shell.

Initial Comment:
After being somewhat dumbfounded by the fact that there
is no easy way to securely give user input as
parameters to an external utility (because of the fact
that os.popen*() runs things in the shell), I was happy
to find that (os | popen2).popen[234]() will accept
either a string as the command and execute it within a
shell, or a string list which is executed directly.

This does not apply to os.popen(), however
popen2.popen[234]() all use this piece of code to
execute the command in the child process:

/usr/lib/python2.2/popen2.py
    def _run_child(self, cmd):
        if isinstance(cmd, types.StringTypes):
            cmd = ['/bin/sh', '-c', cmd]
        for i in range(3, MAXFD):
            try:
                os.close(i)
            except:
                pass
        try:
            os.execvp(cmd[0], cmd)
        finally:
            os._exit(1)

Meaning that unless cmd is a string it will be run
directly, outside of any shell.

This appears to be the case for os.popen[234]() as well
as popen2.popen*()

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https://sourceforge.net/tracker/?func=detail&atid=105470&aid=666700&group_id=5470