[ python-Bugs-850110 ] Out of order commands excecution?

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Bugs item #850110, was opened at 2003-11-27 08:54
Message generated for change (Comment added) made by nadavhoresh
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Category: Parser/Compiler
Group: Python 2.3
>Status: Open
Resolution: Invalid
Priority: 5
Submitted By: Nadav Horesh (nadavhoresh)
Assigned to: Michael Hudson (mwh)
Summary: Out of order commands excecution?

Initial Comment:
Consider the following:

>>> import string
>>> def test1():
	join = string.join

	
>>> def test2():
	join = string.join
	string = string.split

	
>>> test1()
>>> test2()

Traceback (most recent call last):
  File "<pyshell#9>", line 1, in -toplevel-
    test2()
  File "<pyshell#7>", line 2, in test2
    join = string.join
UnboundLocalError: local variable 'string' referenced
before assignment
>>> 

How the second statement in test2 generates an error in
first one?

  Nadav.

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>Comment By: Nadav Horesh (nadavhoresh)
Date: 2003-11-30 19:26

Message:
Logged In: YES 
user_id=75473

I've looked at the FAQ and it is not seems to sesolve the
issue: In test2 "string" becomes a local variable in the
second line, while in the first line (join = string.join)
"string" should point to the (global) string module.

  Nadav.

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Comment By: Michael Hudson (mwh)
Date: 2003-11-27 12:09

Message:
Logged In: YES 
user_id=6656

Well, that's just how it works.  This must be documented
somewhere... see if 

http://www.python.org/doc/faq/programming.html#what-are-the-rules-for-local-and-global-variables-in-python

helps (and maybe the question before).

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