[ python-Bugs-1368368 ] prompt_user_passwd() in FancyURLopener

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Bugs item #1368368, was opened at 2005-11-28 17:39
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Category: None
Group: Python 2.5
Status: Open
Resolution: None
Priority: 5
Submitted By: Björn Lindqvist (sonderblade)
Assigned to: Nobody/Anonymous (nobody)
Summary: prompt_user_passwd() in FancyURLopener

Initial Comment:
Currently, urllib.urlopen() "kind of" handles HTTP
authentication. You simply write something like this:

urllib.urlopen("http://foo:bar@www.moo.com")

And it works like a charm. EXCEPT when the
username/password is wrong. Then you get the
FancyURLopener.prompt_user_passwd()-prompt asking you
for your username and password. I think that behaviour
is extremely illogical and annoying because it forces
you to add more code just to circumvent the odd default
behaviour.

I would be MUCH happer if, instead of the prompt, you
get an exception or the 401 Unauthorized error page
returned.

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You can respond by visiting: 
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