[ python-Bugs-1289118 ] timedelta multiply and divide by floating point
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Tue Sep 13 06:11:30 CEST 2005
Bugs item #1289118, was opened at 2005-09-12 16:41
Message generated for change (Comment added) made by rhettinger
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Category: Python Library
Group: None
Status: Open
Resolution: None
Priority: 5
Submitted By: Daniel Stutzbach (agthorr)
>Assigned to: Tim Peters (tim_one)
Summary: timedelta multiply and divide by floating point
Initial Comment:
In python 2.4.1, the datetime.timedelta type allows for
the multiplication and division by integers. However,
it raises a TypeError for multiplication or division by
floating point numbers. This is a counterintutive
restriction and I can't think of any good reason for it.
For example:
>>> import datetime
>>> datetime.timedelta(minutes=5)/2
datetime.timedelta(0, 150)
>>> datetime.timedelta(minutes=5)*0.5
Traceback (most recent call last):
File "<stdin>", line 1, in ?
TypeError: unsupported operand type(s) for *:
'datetime.timedelta' and 'float'
----------------------------------------------------------------------
>Comment By: Raymond Hettinger (rhettinger)
Date: 2005-09-12 23:11
Message:
Logged In: YES
user_id=80475
Tim, do you prefer the current behavior?
----------------------------------------------------------------------
You can respond by visiting:
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