[issue2706] datetime: define division timedelta/timedelta

[Alexander Belopolsky]

Alexander Belopolsky <belopolsky at users.sourceforge.net> added the comment:

Also, why not

>>> divmod(timedelta(3), 2)
(datetime.timedelta(1), datetime.timedelta(1))

?

And where do we stop? :-)

On Fri, Nov 14, 2008 at 1:02 PM, Alexander Belopolsky
<belopolsky at users.sourceforge.net> wrote:
> On Fri, Nov 14, 2008 at 12:51 PM, STINNER Victor 
<report at bugs.python.org> wrote:
>>
>> STINNER Victor <victor.stinner at haypocalc.com> added the comment:
>>
>> Why not also implementing divmod()? It's useful to split a timedelta
>> into, for example, (hours, minutes, seconds):
>
> I agree and in this case mod should probably be implemented too.
>
> With your patch:
>
>>>> timedelta(3)%timedelta(2)
> Traceback (most recent call last):
>  File "<stdin>", line 1, in <module>
> TypeError: unsupported operand type(s) for %: 'datetime.timedelta' and
> 'datetime.timedelta'
>

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Python tracker <report at bugs.python.org>
<http://bugs.python.org/issue2706>
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