[issue2706] datetime: define division timedelta/timedelta

[Alexander Belopolsky]

Alexander Belopolsky <belopolsky at users.sourceforge.net> added the comment:

While I agree that divmod may be useful, your particular use case is
not convincing. The same can be done easier without divmod:

def formatTimedelta(delta):
   return "{0}h {1}min {2}sec".format(*str(delta).split(':'))

or you can convert delta to time using an arbitrary anchor date and
extract hms that way:

(1, 24, 19)

(depending on your needs you may want to add delta.days*24 to the hours)

On Fri, Nov 14, 2008 at 12:51 PM, STINNER Victor <report at bugs.python.org> wrote:
>
> STINNER Victor <victor.stinner at haypocalc.com> added the comment:
>
> Why not also implementing divmod()? It's useful to split a timedelta
> into, for example, (hours, minutes, seconds):
>
> def formatTimedelta(delta):
>    """
>    >>> formatTimedelta(timedelta(hours=1, minutes=24, seconds=19))
>    '1h 24min 19sec'
>    """
>    hours, minutes = divmodTimedelta(delta, timedelta(hours=1))
>    minutes, seconds = divmodTimedelta(minutes, timedelta(minutes=1))
>    seconds, fraction = divmodTimedelta(seconds, timedelta(seconds=1))
>    return "{0}h {1}min {2}sec".format(hours, minutes, seconds)
>

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<http://bugs.python.org/issue2706>
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