[issue6458] With logging.config.fileConfig can't create logger without handler

[Sean]

New submission from Sean <sean.davis15 at googlemail.com>:

Using "logging" module I can do the following:

    f = logging.Formatter("%(levelname)s: %(name)s: %(message)s")
    h = logging.StreamHandler()
    h.setLevel(logging.NOTSET)
    h.setFormatter(f)
    l = logging.getLogger()
    l.addHandler(h)

    l2 = logging.getLogger('x.y.z')
    l2.setLevel(logging.INFO)
    print len(l2.handlers)

    l2.critical('critical')
    l2.error('error')
    l2.warning('warning')
    l2.info('info')
    l2.debug('debug')

Note, the l2(x.y.z) logger does not have a handler (it just propagates
to the l(root) logger's handler) but the l2 logger does have a different
level set.

When I try to do this with logging.config.fileConfig it fails saying I
have not specified a handler for the x.y.z logger.  But I don't want to
specify a handler, I just want to set the level and have it propagate up
the hierarchy.

Am I doing something wrong?

Sean.

P.S. Here is the config file:

[loggers]
keys=root,xyz

[handlers]
keys=consoleStderr

[formatters]
keys=simpleFormatter

[logger_root]
level=NOTSET
handlers=consoleStderr

[logger_xyz]
level=DEBUG
qualname=x.y.z

[handler_consoleStderr]
class=StreamHandler
level=NOTSET
formatter=simpleFormatter
args=(sys.stderr,)

[formatter_simpleFormatter]
%(levelname)s: %(name)s: %(message)s

----------
messages: 90392
nosy: sean
severity: normal
status: open
title: With logging.config.fileConfig can't create logger without handler
type: behavior
versions: Python 2.6

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Python tracker <report at bugs.python.org>
<http://bugs.python.org/issue6458>
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