[issue9653] New default argparse output to be added
Steven Bethard
report at bugs.python.org
Mon Aug 23 00:06:39 CEST 2010
Steven Bethard <steven.bethard at gmail.com> added the comment:
Sorry, typo. Should have been len(sys.argv) == 1. Full script:
import argparse
import sys
parser = argparse.ArgumentParser()
parser.add_argument('--foo')
if len(sys.argv) == 1:
parser.print_help()
else:
print(parser.parse_args())
With that script, I see:
$ ./python.exe temp.py
usage: temp.py [-h] [--foo FOO]
optional arguments:
-h, --help show this help message and exit
--foo FOO
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