[issue9909] request for calendar.dayofyear() function

[Raymond Hettinger]

Raymond Hettinger <rhettinger at users.sourceforge.net> added the comment:

"We already got one, and it's very nice-a"

ISTM, this should be done with regular date arithmetic in the datetime module.

>>> date(1964, 7, 31) - date(1963, 12, 31)
datetime.timedelta(213)

I don't see why we need a new function for this or why it would be put in the calendar module (where some of its functions have been supplanted by the datetime module).

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nosy: +rhettinger
priority: normal -> low

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<http://bugs.python.org/issue9909>
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