[issue11849] glibc allocator doesn't release all free()ed memory
Antoine Pitrou
report at bugs.python.org
Fri Nov 25 13:52:56 CET 2011
Antoine Pitrou <pitrou at free.fr> added the comment:
Ah, sorry, false alarm. "b[:] = b" actually makes a temporary copy of the bytearray when assigning to itself (!).
However, there's still another strange regression:
$ ./python -m timeit \
-s "n=300000; f=open('10MB.bin', 'rb', buffering=0); b=bytearray(n)" \
"f.seek(0);f.readinto(b)"
-> default branch:
10000 loops, best of 3: 43 usec per loop
-> default branch with patch reverted:
10000 loops, best of 3: 27.5 usec per loop
FileIO.readinto executes a single read() into the passed buffer.
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<http://bugs.python.org/issue11849>
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