[issue18310] itertools.tee() can't accept keyword arguments

[Mark Lawrence]

Mark Lawrence added the comment:

>From the glossary

Quote

keyword argument: an argument preceded by an identifier (e.g. name=) in a function call or passed as a value in a dictionary preceded by **. For example, 3 and 5 are both keyword arguments in the following calls to complex():

complex(real=3, imag=5)
complex(**{'real': 3, 'imag': 5})

End Quote

>From itertools docs "itertools.tee(iterable, n=2) Return n independent iterators from a single iterable", so what is this if it's not a keyword argument?  Surely all that's needed in this case is for the docs to read "itertools.tee(iterable[, n]) Return n independent iterators from a single iterable where n defaults to 2"

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Python tracker <report at bugs.python.org>
<http://bugs.python.org/issue18310>
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