[issue22114] You cannot call communicate() safely after receiving an exception (EINTR or EAGAIN)

R. David Murray report at bugs.python.org
Thu Jul 31 18:11:18 CEST 2014


R. David Murray added the comment:

By the definition of the (blocking) communicate API, communicate can only be called once (it feeds in all the input, and reads all the output).

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<http://bugs.python.org/issue22114>
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