[issue23372] defaultdict.fromkeys should accept a callable factory

[Serhiy Storchaka]

Serhiy Storchaka added the comment:

It may be written simpler:

    d = defaultdict(factory)
    for i in constants:
        d[i]

or

    d = defaultdict(factory, {i: factory() for i in constants})

I'm inclined to reject this proposition. It serves very special use case.

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nosy: +serhiy.storchaka

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<http://bugs.python.org/issue23372>
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