[issue23521] OverflowError from timedelta * float in datetime.py

[Alexander Belopolsky]

Alexander Belopolsky added the comment:

I've got it:

>>> import sys
>>> sys.modules['_datetime'] = None
>>> from datetime import *
>>> td = timedelta(seconds=1)
>>> print(td / (1/0.6112295))
0:00:00.611230

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<http://bugs.python.org/issue23521>
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